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22y^2+93y=85
We move all terms to the left:
22y^2+93y-(85)=0
a = 22; b = 93; c = -85;
Δ = b2-4ac
Δ = 932-4·22·(-85)
Δ = 16129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16129}=127$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(93)-127}{2*22}=\frac{-220}{44} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(93)+127}{2*22}=\frac{34}{44} =17/22 $
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